Problem
The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return [0,1,3,2]. Its gray code sequence is:
00 - 0
01 - 1
11 - 3
10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example, [0,2,3,1] is also a valid gray code sequence according to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
Code
vector<int> grayCode(int n) { // IMPORTANT: Please reset any member data you declared, as // the same Solution instance will be reused for each test case. if(n == 0) return vector<int>(1,0); vector<int> ret = grayCode(n - 1); vector<int> result; copy(ret.begin(),ret.end(),back_inserter<vector<int> >(result)); vector<int>::const_reverse_iterator it = ret.rbegin(); int one = (1 << (n - 1)); for(;it != ret.rend();++it){ result.push_back(one | *it); } return result; }
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