Problem
There are N gas stations along a circular route, where the amount of gas at station i is
gas[i]
.
You have a car with an unlimited gas tank and it costs
cost[i]
of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
The solution is guaranteed to be unique.
Code
int canCompleteCircuit(vector<int> &gas, vector<int> &cost) { // Note: The Solution object is instantiated only once and is reused by each test case. int n = gas.size(); for(int i = 0;i < n; ++i){ int sum = 0; int j = 0; for(;j < n; ++j){ int k = (i + j < n) ? (i + j) : (i + j - n); sum += (gas[k] - cost[k]); if(sum < 0) break; } if(j == n) return i; } return -1; }
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